\( Geg.:\\ U=5V\\ I=2A\\ t=24h \cdot365 =8760h\\ K_{kWh}= \frac{0,25€}{kWh} \\ Ges.:\\ W_{el.} = ?\\ K_a=?\\ Lös.:\\ W_{el.} = U \cdot I \cdot t= 5V \cdot2A \cdot 8760h=87.600VAh= 78,6kWh\\ K_a = 78,6kWh \cdot \frac{0,25€}{kWh} =21,9€ \)

Last modified: Wednesday, 24 November 2021, 8:41 PM